Physics 4B 03/05/14

 03/05/14 Lab was about determining how hot the apparatus will get when volume is decreased in a rapid succession. This will include the picture of the apparatus, calculations, and a video of the experiment   

 This is a picture of the apparatus. A person would push down on the know to reduce the volume.

This is our calcualtions we using the formula ViTi^(3/2) = VfTf^(3/2)  solving for Tf  = ([VfTf^(3/2)]/Vi)^2/3

The temperature we would reach from our calculations were 1381.8 +/- 2.036 Kelvin. 

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