Physics 4B 022614

Thermal Expansion and Latent heat

Experiment one 

  Experiment one: Involved a ring and a ball. Previously the ball could not pass through the ring. It begged the question what will happen when the ring is heated. We guests it would expand the ring. According to the picture above the ring did expand and the ball passed through.

Another experiment on how a metal will react to heat. This one is different because there were two metals on a flattened rod; one on each side. Having two different metals when heated one metal expanded faster than the other therefore bent one way then bent back when dunked in cold water.

    This picture shows the apparatus of a hollow metal pole being heated with steam. The point of this experiment is to figure out how much the metal pole expanded. The opposite side of the metal rod is connected to rotary motion  pulley. Using the angular displacement we can see how much the metal expanded

 This is the symbolic equations that we used to calculate how much the rod has changed. With the displacement we could find alpha which is the coefficient of linear expansion. We found our that the metal bar is aluminum.

This is where the graph would be but only the change in degrees and temp were recorded (displayed above ( change in temp is 76 degrees and angular displacement of 17 degrees)

materials used: 1 meter hollow aluminum metal rod, a 1.5mm diameter rotary metal pulley, temperature probe, and  logger pro measuring angular displacement and temperature.

*need to add propagation*
use largest and smallest to get propagation


 The second half of the class displayed the different properties of pressure in relation to temperature and volume.

Latent heat


Next experiment was heating a cup of ice water

Prediction of what will happen when heated

This displace our temperature versus time

This is pressure versus volume 

Pressure versus volume experiment 

This is temperature versus pressure  experiment

This picture shows the latent heat of vaporization of water. Our calculation of 3.86x10^6 seemed like an out-liar and using standard deivation of find uncertainty we were still not within the actual latent heat of water of 2.26x10^6.