032414

 Chart of converting the different angles of the steel wire from degrees to Radians

 This is a picture of the flux versus angle graph which depicts a cosine graph. According to the data sheet the the higher the angle the less flux will be present in the wire. With forty-nine flux the angle is zero and going to the max of seven the angle is pi/2 ( 90 degrees). A person could conclude that the closer the area( wire square) is parallel to the nails pointing the less flux a will go through.

 This is a picture of activphysics 11.7 questions

link: http://media.pearsoncmg.com/bc/aw_young_physics_11/pt2a/Media/Electricity/1107ElecFlux/Main.html

03/19/14

Activ physics answers to 

11.4 Electric Field: Point Charge

Excel assignment of predicting electrical fields

 The point of this excel assignment was to find the electrical field of a charge perpendicular to a pole. Depending on the distance the spreadsheet would be a quick reference.

   This is my 16th attempt I was unclear of the rules so I just paused it and moved the negative charge and maneuvered it to the goal.

 Attempt two on the second challenge unclear of the rules but did it with one

031714

This is the video we analysed. It depicts the movement of a handing ball being repelled by another ball.

Video analysis logger pro

This is a graph of force versus time of video analysis. The graph depicts that the force increases as the ball became closer to stationary hanging ball.

Conclusion:

031214 Diesel Cycle

Diesel Cycle Problem 

Diesel Cycle Calculations 

 This picture shows the step process I used to get the individual: pressures, volumes, and temperatures for the four different points

This is a picture of which equations used for calculating Work, Heat Energy, Change in Energy, and Entropy. I tried to rotate the image but it didn't  work

Physics 4B 031014

Today we discussed what a Carnot cycle was and different activites in activ phyiscs.  

 This is a picture of our Pressure versus Volume graph. Point A to B (C to D) is an isothermal process, B to C (D toA)  is an adiabatic process. For each transition (A to B) we could calculated: the Change in energy, Work and Heat energy. Errors are C is equal to 2496 J,  From B to C where Q = 0  resulting in a change in energy equal to Work -1243 J. From C to D: Q = 1825 J, W= -1823.8, change in Energy = 1.77 J. (D to A) Q = 0 , change in Energy = -W.    

Question 6: Heat and Temperature Change Numbers
 Record the heat transfer that has already occurred and the present temperature. Then RUN the simulation again and quickly stop it. Record the heat transferDQ and temperature again. Repeat the process several times. Use the numbers you have obtained to estimate the constant pressure molar specific heat capacity of this ideal gas. Calculated to be 20.78 J/mol/K.

Question 7: A More Accurate Heat Capacity Measurement

 Make an accurate calculation of the constant pressure molar heat capacity of the ideal gas. When you are finished, compare your answer to that of the Advisor. Our results for Cp was 20.775 J/mol/K

Our goal was to rearrange the above equation to result in 3/2R + R which turned out to be 20.77 J/mol/K

Out 

Physics 4B 03/05/14

 03/05/14 Lab was about determining how hot the apparatus will get when volume is decreased in a rapid succession. This will include the picture of the apparatus, calculations, and a video of the experiment   

 This is a picture of the apparatus. A person would push down on the know to reduce the volume.

This is our calcualtions we using the formula ViTi^(3/2) = VfTf^(3/2)  solving for Tf  = ([VfTf^(3/2)]/Vi)^2/3

The temperature we would reach from our calculations were 1381.8 +/- 2.036 Kelvin. 

questions from activ physics

Physics 4B 03/03/14

need to add the propagtion for the uncertainty for change for volume

units of r value of graph

PV=nRT

graph of volume versus temperature

V/T = nR/P

(mol*J*m^2)/(mol*N*K) = (J*m^2)/N*K

J = N*m

(N*m^3)/(N*K)

= m^3 / K

This unit makes sense because volume is in meters cubed and temperature is in kelvin

The units of R(From the graph) 8.3671 are a combination of volume (m^3) and Temp( Kelvin).

Physics 4B 022614

Thermal Expansion and Latent heat

Experiment one 

  Experiment one: Involved a ring and a ball. Previously the ball could not pass through the ring. It begged the question what will happen when the ring is heated. We guests it would expand the ring. According to the picture above the ring did expand and the ball passed through.

Another experiment on how a metal will react to heat. This one is different because there were two metals on a flattened rod; one on each side. Having two different metals when heated one metal expanded faster than the other therefore bent one way then bent back when dunked in cold water.

    This picture shows the apparatus of a hollow metal pole being heated with steam. The point of this experiment is to figure out how much the metal pole expanded. The opposite side of the metal rod is connected to rotary motion  pulley. Using the angular displacement we can see how much the metal expanded

 This is the symbolic equations that we used to calculate how much the rod has changed. With the displacement we could find alpha which is the coefficient of linear expansion. We found our that the metal bar is aluminum.

This is where the graph would be but only the change in degrees and temp were recorded (displayed above ( change in temp is 76 degrees and angular displacement of 17 degrees)

materials used: 1 meter hollow aluminum metal rod, a 1.5mm diameter rotary metal pulley, temperature probe, and  logger pro measuring angular displacement and temperature.

*need to add propagation*
use largest and smallest to get propagation


 The second half of the class displayed the different properties of pressure in relation to temperature and volume.

Latent heat


Next experiment was heating a cup of ice water

Prediction of what will happen when heated

This displace our temperature versus time

This is pressure versus volume 

Pressure versus volume experiment 

This is temperature versus pressure  experiment

This picture shows the latent heat of vaporization of water. Our calculation of 3.86x10^6 seemed like an out-liar and using standard deivation of find uncertainty we were still not within the actual latent heat of water of 2.26x10^6.